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B l o w i n g

S n o w

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EXPERIMENT OUTLINE

Thepurposeoftheexperimentpresentedherewasto
measure the charge-to-mass ratioon an individual blow-
ingsnowparticle.Inhisfamousexperiment,Millikan
(1910)measuredthe chargeofsingle electronsfromthe
motionofoildropsmovinginaconstantelectricfield.
Camp (1977)used a variation on thistechnique to deter-
mine charge-to-mass ratios for falling snow crystals.Based
on theirmethods we designed the apparatus and experi-
ment described below to measure the the charge on drift-
ing particles.Snow particles were extractedfrom saltation
byadrifttrap.Particlesthatdidnotimpactthetrap
droppedvertically through a still air chamber containing a
constanthorizontalelectricfield.Adetectortriggered a
photographic imaging system that produced photographs
showingparticlepath and location atknown timeinter-
vals.Chargedparticlearedeflected horizontallybyan
amount proportional to their charge, with direction deter-
minedbythe charge sign.Photographs showing deflec-
tion both left and right would confirm our hypothesis that
positiveandnegativecharged particlesaretransported
simultaneouslyin saltation.The charge-to-mass ratio of
theparticlecan bedeterminedfromtheseimagesusing
equations derived in the next section.


EQUATIONS OF MOTION

A charged particle falling through still air, with a horizon-
tal electric field,is acted upon by the gravitational force,
an electrostatic force, and a drag force dueto air resistance
thatopposestheparticlesmotion.Ifthedirectionthe

particle travels isdefined by an angle q with the vertical
(figure 1), the equations that describe the particle's motion
are
F
E-Fdsinq =m x..
(1)

and

The magnitude of the electrostatic force is FE= qE, where
E is the magnitude of the electric field and q is the charge
ontheparticle.Fornon-spherical particlestravelingat
low speed, the magnitudeof the drag forcecan be approxi-
mated as Fd= k(3
pm )dnv (McNown,et.al.,1951).Here k
denotes the shape factorof the particle,
mis the dynamic
viscosity of air, dnis the particle's nominal diameter, and v
is the velocity of the particle.Substitutingtheseexpresions
into equations (1) and (2) gives


qE
and
-k x(3
pm)dnvsinq =m x..
..
mg
-ky(3 pm ) dnv cosq=m y

(3)

(4)

(v)sinq and (v)cosq are the horizontal and vertical compo-
nents of particle velocity so that


qE
and
-kx(3
pm)dnx.
=m x..
...
mg
-ky(3 pm)dny=m y

(5)

(6)

Assumingtheparticlefallsatterminalvelocityv,the
vertical component of acceleration is zero, andthe verT
tical
componentofvelocityisconstant.Equation(6)then
becomes mg = ky(3
pm )dnvTwhich can be rearranged as

IMAGE Imgs/art_29_05.gif
= IMAGE Imgs/art_29_06.gif (7)

m(3
pm)dnvT

IMAGE Imgs/art_29_07.gif


mg-Fdcosq =my..

(2)


Equation (8) expresses the motion of the particle in terms
of the variables E and vT(which can be measured experi-
mentally) and the ratio q/m which we wish to determine.
Equation (8) is solved by separation of variable.Forbrev-
ity, we define thetwo constant expressions in equation (8)
asE(q/m)=aand (g/vT)=b.Substitutingtheseexpres-
sions into equation (8),separating variables, and integrat-
ing both sides of the resulting expression gives

IMAGE Imgs/art_29_08.gif

dx·
[!]------
a - bx
·=[!] dt

T=---1n[a-bx1·
b]+c1

or

(9)

Weevaluate the constant of integration c1by assuming the
x - component of velocityis very small when the particle
enterstheelectricfield.Attimet=0,X=0therefore
c1 =ln[a]/b. Expression (9) becomes t = -(1/b) 1n[(a-bx)/a].
Exponentiating both sides this expression yields
1- e-b t= (b/a) x, or


Figure 1: Free-body diagram of particle falling in air, subject to a

constant electrostatic force.


130

1-e- b t=(--)---bdx
adt

(10)