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taken twice a day (9:00 am and 1:00 pm) as well as various
other measurements.
So we can perform quite significant tests from this in-
formation.
Our sample consists of 123 days with 140 avalanches
for 1111 release attempts. Obviously, we selected days
without significant snowfall to eliminate statistical noise.

2.2. PROCEDURE

Wecalculated, for eachday from the sample, an avalanche
activity index as following:
Acti = nAval / nEvent
where
nAval is the number of observed avalanches(arti-
ficially released or not),
nEvent is the sum: (number of release attempts) +
(number of natural avalanches).
For example, duringMarch7th 1995, 7 avalanches were
observed for 9 release attempts and no natural avalanche
occurred: theavalancheactivity index was 0.78; the snow-
drift index was 30 g, the wind speed was nil, andthe wind
speed the day before was 15 knots.
We completed charts to visualise the statistical distri-
butions of avalanche activity accordingto wind speed and
snowdrift (fig.6).
The charts confirms that avalanche activity strongly
depends on snowdrift which seems to be more informa-
tive than wind. Now let us quantify this intuitive deduc-
tion and let us turn to an index of association in the pre-
dictive sense.
Let us assume that our sample is large enough to con-
sider that frequenciesand probabilities of events are equal
and let us describe the distributions by the mean of joint
probability distribution tables (fig.7).
Let us now characterise the relationship betweensnow-
drift and avalancheactivity. The index of predictive asso-
ciation developed by Goodman and Kruskal is:
lAS = [P(e) - P(e|S)] / P(e) [1]
where
.S is the snowdrift index given by the driftometer,
.P(e) is the lowest probability of an error in avalanche
activity classification when S is unknown;
P(e)=1-max [!] P
(Pij : probabilityij
from cell [Si, Aj]) [2]
.P(e | S) is the lowest probability of an error in ava-
lanche activity classification when S is known;
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P(e|S)=[P(e|So).P(So)+P(e|S1).P(S1)]/[P(So)+P(S1 )]
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